# kCbbbf_11
# kCbbbf_11_num=3
c += 1
kCbbbfr[c] = row+0
kCbbbfc[c] = col+0
kCbbbfv[c] += 0.5*a*kt*pAu*pBu*qAu*qBu
c += 1
kCbbbfr[c] = row+1
kCbbbfc[c] = col+1
kCbbbfv[c] += 0.5*a*kt*pAv*pBv*qAv*qBv
c += 1
kCbbbfr[c] = row+2
kCbbbfc[c] = col+2
kCbbbfv[c] += 0.5*a*kt*(pAw*pBw*qAw*qBw + 4*kr*pAw*pBw*qAweta*qBweta/((bb*bb)*kt))